# 1.9 Age Problems

A marble bust is 25 years old, and a terra-cotta bust is 85 years old. In how
many years will the terra-cotta bust be three times as old as the marble bust?

A boy is 10 years older than his brother. In 4 years he will be twice as old as
his brother. Find the present age of each.

The sum of Clyde and Wendy’s age is 64. In four years, Wendy will be three
times as old as Clyde. How old are they now?

Chelsea’s age is double Daniel’s age. Eight years ago the sum of their ages
was 32. How old are they now?

A is now 34 years old, and B is 4 years old. In how many years will A be
twice as old as B?

A man’s age is 36 and that of his daughter is 3 years. In how many years will
the man be 4 times as old as his daughter?

The sum of the ages of a china plate and a glass plate is 16 years. Four years
ago the china plate was three times the age of the glass plate. Find the
present age of each plate.

A father is 4 times as old as his son. In 20 years the father will be twice as old
as his son. Find the present age of each.

Diane is 23 years older than her daughter Amy. In 6 years Diane will be twice
as old as Amy. How old are they now?

A log cabin quilt is 24 years old and a friendship quilt is 6 years old. In how
may years will the log cabin quilt be three times as old as the friendship
quilt?